SOLUTION: One side of a larger square is 8 cm longer than a side of a smaller square. Find the dimensions of both squares if the sum of their perimeters is 128 cm

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Question 1088332: One side of a larger square is 8 cm longer than a side of a smaller square. Find the dimensions of both squares if the sum of their perimeters is 128 cm
Answer by ikleyn(52781) About Me  (Show Source):
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Let x be the side length of the smaller square, in centimeters.

Then the length of the larger square is (x+8) cm.


The perimeter of the small square is 4x centimeters.

The perimeter of the larger square is 4(x+8) cm.


 We are given the sum of the perimeters:

4x + 4(x+8) = 128   cm.


Simplify and solve for x:

4x + 4x + 32 = 128  ====>  8x = 128 - 32  ====>  8x = 96  ====>  x = 96%2F8 = 12.


Answer.  The side length of the smaller square is 12 cm.

         The side length of the larger square is 12+8 = 20 cm.

Solved.