SOLUTION: The length of a rectangle is 4 square greater than the width. If each dimension is increased by 3 the new area will be 33 square inches larger. Find the dimensions of the original

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 4 square greater than the width. If each dimension is increased by 3 the new area will be 33 square inches larger. Find the dimensions of the original       Log On


   

Question 1088208: The length of a rectangle is 4 square greater than the width. If each dimension is increased by 3 the new area will be 33 square inches larger. Find the dimensions of the original rectangle.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
L=4%2BW
For a rectangle,
A=L%2AW
So,
LW%2B33=%28L%2B3%29%28W%2B3%29
Substituting from above,
%284%2BW%29W%2B33=%284%2BW%2B3%29%28W%2B3%29
4W%2BW%5E2%2B33=%28W%2B7%29%28W%2B3%29
W%5E2%2B4W%2B33=W%5E2%2B10W%2B21
4W%2B33=10W%2B21
6W=12
W=2in
So then,
L=4%2B2
L=6in