SOLUTION: The length of a rectangle is 8.03 inches more than half of its width. If the perimeter is 37.48 inches
Find the demensions
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Find the demensions
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Question 1082657: The length of a rectangle is 8.03 inches more than half of its width. If the perimeter is 37.48 inches
Find the demensions Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! 2L + 2W = Perimeter
L = 1/2W + 8.03 substitute for L above:
2(1/2W + 8.03) + 2W = 37.48
W + 16.06 + 2W = 37.48
3W = 21.42
W = 7.14
L = 1/2W + 8.03 = 1/2(7.14)+8.03 = 11.6
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Check:
2L + 2W = 37.48
2(7.14) + 2(11.6) = 37.48 Correct
