SOLUTION: A rectangle with an area of 64 cm² has a length that is 8 cm more than twice it's with. Find the length, width and perimeter of the rectangle.

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Question 1080632: A rectangle with an area of 64 cm² has a length that is 8 cm more than twice it's with. Find the length, width and perimeter of the rectangle.
Answer by rapture(86) About Me  (Show Source):
You can put this solution on YOUR website!
Length = 2x + 8

Width = x

Area = 64

Solve 64 = x(2x + 8) for x.

Then plug x-value into

P = 2(2x + 8) + 2x to find the perimeter.

You finish.