SOLUTION: the area of a rectangle patio A(p)=32 p-p^2 where A(p) is the area in square meters and p is the width of the rectangle in meters
a) what dimensions give the maximum area of the p
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-> SOLUTION: the area of a rectangle patio A(p)=32 p-p^2 where A(p) is the area in square meters and p is the width of the rectangle in meters
a) what dimensions give the maximum area of the p
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Question 1078207: the area of a rectangle patio A(p)=32 p-p^2 where A(p) is the area in square meters and p is the width of the rectangle in meters
a) what dimensions give the maximum area of the patio
b) what is the maximum area of the patio Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! The area is maximized when dA/dp = 0 = 32 - 2p -> p = 16 m
Therefore the area is A(16) = 32*16 - 16^2 = 256 m^2
Since area = l*w, the length is also 16 m
Ans: length, width = 16 m; Area = 256 m^2
