Question 1076140: the perimeter of the rectangle if the width is twice the root of the length and the area is 250 Found 3 solutions by mananth, ikleyn, josgarithmetic:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! the width is twice the root of the length and the area is 250
length be x
width =
Area = 250
x*2sqrt(x)=250
square both sides
4x^3= 250*250
x^3= 125*125
x = sqrt(125*125)
x=25 the length
width = 2*sqrt(x)
= 2*sqrt(25)
=10 the width
You can put this solution on YOUR website! . the perimeter of the rectangle if the width is twice the root of the length and the area is 250.
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The answer in the post by @mananth is correct, but on the way he made errors
that shocked me. I afraid that they shoked you, too.
Therefore, I came to present the solution in a correct form.
Read my solution attentively; watch every my step and find the differences between
my solution and that by @mananth.
Let the length be x.
Then the width = .
Area = 250: = 250.
Square both sides
4x^3 = 250*250,
x^3 = 125*125 = = ,
x = = 25 the length.
width = = = 2*5 = 10.
the width = 10.
The perimeter = 25 + 10 + 25 + 10 = 70. ANSWER
You can put this solution on YOUR website! ---------------------------------------------------------------
the width is twice the root of the length and the area is 250.
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