SOLUTION: The width, w, of a rectangle is 4 cm shorter than the length,l. If the area of the rectangle is 60 centimeters squared, which equation models the situation correctly?

Algebra ->  Rectangles -> SOLUTION: The width, w, of a rectangle is 4 cm shorter than the length,l. If the area of the rectangle is 60 centimeters squared, which equation models the situation correctly?      Log On


   

Question 1057733: The width, w, of a rectangle is 4 cm shorter than the length,l. If the area of the rectangle is 60 centimeters squared, which equation models the situation correctly?
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
If the length is l, then w, width, equals l-4. So your equation looks like:
A=l x w
60= l(l-4)
Solving, we get:
lē-4l-60=0
(l-10)(l+6)=0
l=10, -6
Your length is 10 cm, width is 6 cm. ☺☺☺☺