SOLUTION: One half area of a rectangular garden is 54m . If the triple of the width exceeds twice the length by 3 meter , Find the perimeter
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Question 1053838: One half area of a rectangular garden is 54m . If the triple of the width exceeds twice the length by 3 meter , Find the perimeter Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! 3w= 2L + 3
(3w-3)/2 = L
w(3w-3)/2 = 108
w(3w-3) = 216
3w^2 - 3w - 216= 0
w^2 - w - 72 = 0
(w-9)(w+8) = 0
w = 9m and L = 12m
P = 2L + 2w
P = 18m + 24m = 42m
