SOLUTION: The length of a rectangle exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than t
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Question 1050425: The length of a rectangle exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle find the dimensions for the original rectangle Answer by advanced_Learner(501) (Show Source):
You can put this solution on YOUR website! The length of a rectangle exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle find the dimensions for the original rectangle
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original rectangle
L-w=4
p=2L+2w
p=
2w
L-2
p=
then it says
2L+4w-4= 8+4w+8
L=10
original rec
L=10
W=6
check
your self!
