SOLUTION: the perimeter of a rectangle is 28 feet. if the width is 3ft and the length is (2+x)ft, what is the value of x?

Algebra ->  Rectangles -> SOLUTION: the perimeter of a rectangle is 28 feet. if the width is 3ft and the length is (2+x)ft, what is the value of x?      Log On


   

Question 1050061: the perimeter of a rectangle is 28 feet. if the width is 3ft and the length is (2+x)ft, what is the value of x?
Found 2 solutions by ewatrrr, advanced_Learner:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

     .

2w + 2L = P

2x + 2(x+2) = 28ft

2x + 2x+ 4 = 28ft

4x = 24ft

x = 6ft, the value of x 

Checking.. L = 8ft 6%2B2

2w + 2L = P

12ft + 16ft = 28ft CHECKS!

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
P=2w+2l

28=2*3+2(2+x)
x=9
so lenght is 11
width is 3
check
28=2*3+2*11