SOLUTION: Rectangle ABCD is twice as long and four times as wide as rectangle JKLM. Find the dimensions of each rectangle, if their perimeters are 48cm and 20 cm respectively.

Algebra ->  Rectangles -> SOLUTION: Rectangle ABCD is twice as long and four times as wide as rectangle JKLM. Find the dimensions of each rectangle, if their perimeters are 48cm and 20 cm respectively.      Log On


   

Question 1043780: Rectangle ABCD is twice as long and four times as wide as rectangle JKLM. Find the dimensions of each rectangle, if their perimeters are 48cm and 20 cm respectively.
Answer by advanced_Learner(501) About Me  (Show Source):
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Rectangle ABCD is twice as long and four times as wide as rectangle JKLM. Find the dimensions of each rectangle, if their perimeters are 48cm and 20 cm respectively.
solution
JKL
20=2L%2B2W first equation
ABCD
48=2%282L%29%2B4%282W%29
48=4L%2B8w second equation
Which gives two equations solving
l=8+and+w=2
verifity
20=2%288%29%2B2%282%29
20=4%2B16 TRUE
48=4%288%29%2B8%282%29 True