SOLUTION: the length of a rectangle is 3 more than twice its width.if the perimeter is to be at 51 meters, what are the possible values for the width?

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Question 1019521: the length of a rectangle is 3 more than twice its width.if the perimeter is to be at 51 meters, what are the possible values for the width?
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
L= 2W+3
and
2L+2W =>51
2(2W+3)+2W => 51
4W+6+2W => 51
6W => 45
W => 7.5
Answer: 7.5, ∞