SOLUTION: The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x2 + 5x = 300. What are the measures of the width and the

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x2 + 5x = 300. What are the measures of the width and the      Log On


   

Question 1013437:
The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x2 + 5x = 300. What are the measures of the width and the length?
Width = a0 inches
Length = a1 inches

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 5 inches more than its width, x.
The area of a rectangle can be represented by the equation x2 + 5x = 300. What are the measures of the width and the length?
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Factor::
x^2 + 5x - 300 = 0
(x-15)(x+20) = 0
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x = 15 is the width.
x+5 = 20 is the length
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Cheers,
Stan H.
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