SOLUTION: the perimeter of a rectangle is 56cm the length of the rectangle is 4 less than 3 times the width find the length the equation is 2(3w-4)+2(w)=56cm find the length 3w-4=_______ cm

Algebra ->  Rectangles -> SOLUTION: the perimeter of a rectangle is 56cm the length of the rectangle is 4 less than 3 times the width find the length the equation is 2(3w-4)+2(w)=56cm find the length 3w-4=_______ cm      Log On


   

Question 1006320: the perimeter of a rectangle is 56cm the length of the rectangle is 4 less than 3 times the width find the length the equation is 2(3w-4)+2(w)=56cm find the length 3w-4=_______ cm I tried the other tutor that answered but for some reason the acellus algebra 1 course won't accept them
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
width=x
length=3x-4
perimeter is 4x-4 doubled or 8x-8=56 cm.
8x=64 cm
x=8 cm width
3x-4=20 cm length.