SOLUTION: the perimeter of a rectangle is 56cm the length of the rectangle is 4 less than 3 times the width find the length the equation is 2(3w-4)+2(w)=56 the find the length 3w-4=______ cm

Algebra ->  Rectangles -> SOLUTION: the perimeter of a rectangle is 56cm the length of the rectangle is 4 less than 3 times the width find the length the equation is 2(3w-4)+2(w)=56 the find the length 3w-4=______ cm      Log On


   

Question 1006268: the perimeter of a rectangle is 56cm the length of the rectangle is 4 less than 3 times the width find the length the equation is 2(3w-4)+2(w)=56 the find the length 3w-4=______ cm
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the perimeter of rectangle is
P=2L%2B2W
so,
2L%2B2W=56cm

if the length of the rectangle is 4 less than 3 times the width, then we have
L=3W-4
2%283w-4cm%29%2B2%28w%29=56cm

6w-8cm%2B2w=56cm
8w=56cm%2B8cm
8w=64cm
w=64cm%2F8
w=8cm
then the length is
L=3%2A8cm-4cm
L=24cm-4cm
L=20cm+