SOLUTION: The perimeter of a rectangle is 268 inches. If each dimension is decreased by 12 inches, one of the dimensions becomes 3/8 of the other. Find the dimensions of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 268 inches. If each dimension is decreased by 12 inches, one of the dimensions becomes 3/8 of the other. Find the dimensions of the rectangle.      Log On


   

Question 1005258: The perimeter of a rectangle is 268 inches. If each dimension is decreased by 12 inches, one of the dimensions becomes 3/8 of the other. Find the dimensions of the rectangle.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
2w+2L=268, and the description then indicates w+12 and L+12 to be the new dimensions.

w%2B12=%283%2F8%29%28L%2B12%29
8w%2B96=3%28L%2B12%29
8w%2B96=3L%2B36
8w-3L=36-96
8w-3L=-60
highlight_green%283L-8w=60%29

Use the perimeter information.
w%2BL=134
L=134-w
-
Substitute
3%28134-w%29-8w=60
402-3w-8w=60
-11w=60-402
11w=402-60
11w=342
highlight%28w=31%261%2F11%29

L=134-31%261%2F11
highlight%28L=102%2610%2F11%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The perimeter of a rectangle is 268 inches. If each dimension is decreased by 12 inches, one of the dimensions becomes 3/8 of the other. Find the dimensions of the rectangle.
Dimensions: highlight_green%28matrix%281%2C5%2C42%2C+inches%2C+and%2C+92%2C+inches%29%29