SOLUTION: Evaluate by partial fraction (5x^2+20x+6)/(x^2(x-2))

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Question 952701: Evaluate by partial fraction
(5x^2+20x+6)/(x^2(x-2))
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%285x%5E2%2B20x%2B6%29%2F%28x%5E2%28x-2%29%29=A%2Fx%2BB%2Fx%5E2%2BC%2F%28x-2%29
5x%5E2%2B20x%2B6=Ax%28x-2%29%2BB%28x-2%29%2BCx%5E2
5x%5E2%2B20x%2B6=Ax%5E2-2Ax%2BBx-2B%2BCx%5E2
5x%5E2%2B20x%2B6=%28A%2BC%29x%5E2%2B%28B-2A%29x-2B
So then,
-2B=6
B=-3
then,
B-2A=20
-3-2A=20
-2A=23
A=-23%2F2
and
A%2BC=5
-23%2F2%2BC=5
C=5%2B23%2F2
C=10%2F2%2B23%2F2
C=33%2F2
So then,