SOLUTION: solve: {{{x+2y=16}}}, {{{(sqrt(x-2))=y-3}}}

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Question 874535: solve:
x%2B2y=16, %28sqrt%28x-2%29%29=y-3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1. x%2B2y=16
2.%28sqrt%28x-2%29%29=y-3
From eq. 2,
x-2=%28y-3%29%5E2
x=2%2B%28y-3%29%5E2
Substitute into eq. 1,
2%2B%28y-3%29%5E2%2B2y=16
2%2By%5E2-6y%2B9%2B2y=16
y%5E2-4y%2B11=16
y%5E2-4y-5=0
%28y-5%29%28y%2B1%29=0
Two solutions:
y-5=0
y=5
Then,
x%2B2%285%29=16
x%2B10=16
x=6
.
.
y%2B1=0
y=-1
Not allowed by the square root function so only one solution.
(6,5)