SOLUTION: Find f'(x): f(x) = x^2 + 5x + 1
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Question 836692
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Find f'(x): f(x) = x^2 + 5x + 1
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jim_thompson5910(35256)
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f(x) = x^2 + 5x + 1
d/dx[f(x)] = d/dx[x^2 + 5x + 1]
f ' (x) = d/dx[x^2 + 5x + 1]
f ' (x) = d/dx[x^2] + d/dx[5x] + d/dx[1]
f ' (x) = 2x + 5 + 0
f ' (x) = 2x + 5