SOLUTION: Multiply (n^2+3n-4)/(n^2-16)*(n^2+3n-4)/(n^2-1) Please I need help with this exercise! Thank you!

Algebra ->  Rational-functions -> SOLUTION: Multiply (n^2+3n-4)/(n^2-16)*(n^2+3n-4)/(n^2-1) Please I need help with this exercise! Thank you!      Log On


   

Question 825868: Multiply
(n^2+3n-4)/(n^2-16)*(n^2+3n-4)/(n^2-1)
Please I need help with this exercise! Thank you!
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
%28n%5E2%2B3n-4%29%2F%28n%5E2-16%29*%28n%5E2%2B3n-4%29%2F%28n%5E2-1%29
Everything will factor, the denominators are "difference of squares"
%28%28n%2B4%29%28n-1%29%29%2F%28%28n-4%29%28n%2B4%29%29*%28%28n%2B4%29%28n-1%29%29%2F%28%28n-1%29%28n%2B1%29%29
Cancel (n+4) and (n-1) leaving
%28%28n-1%29%29%2F%28%28n-4%29%29*%28%28n%2B4%29%29%2F%28%28n%2B1%29%29