Question 82306This question is from textbook Integrated Mathematics 1
: Make a graph by using the line of symmentry, vertex, and intercepts.
The equation is y=x^2-x-2
This question is from textbook Integrated Mathematics 1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Make a graph by using the line of symmentry, vertex, and intercepts.
The equation is y=x^2-x-2
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Complete the square to get:
y = x^2-x+(1/2)^2 -2-(1/2)^2
y = (x-(1/2))^2 -(9/4)
y+(9/4) = (x-(1/2))^2
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Axis of symmetry: x=1/2
Vertex: (1/2,-9/4)
y-intercept: Let x=0, then y=-2
x-intercept: Let y=0, then x=[1+-sqrt(1-4*-2)]/2 = 2 or x = -1
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Cheers,
Stan H.
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