SOLUTION: (x - 4)2/3 power = 16

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Question 70148This question is from textbook College Algebra Essentials
: (x - 4)2/3 power = 16 This question is from textbook College Algebra Essentials

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!

%28x-4%29%5E%282%2F3%29+=+16
.
Cube both sides. In the case of the left side that means multiplying it by itself so that
the multiplications are:
.
%28x-4%29%5E%282%2F3%29%2A%28x-4%29%5E%282%2F3%29%2A%28x-4%29%5E%282%2F3%29
.
But when you multiply a base term [in this case the base is (x-4)] that has an exponent by
the same base term with other exponents, the product is the same base term, but the new
exponent is the sum of the exponents. For example x%5Ea+%2Ax%5Eb%2Ax%5Ec=+x%5E%28a%2Bb%2Bc%29
.
In the case of taking the cube of
%28x-4%29%5E%282%2F3%29
the product will be
.

.
That is it cube of the left side of the original problem. And since we cubed the left
side, we must also cube the right side. 16 cubed is 16%2A16%2A16.
.
We have now converted the original problem to:
.
%28x-4%29%5E2+=+16%2A16%2A16
.
Now take the square root of both sides. The left side becomes just x-4. The first
two terms on the right side are 16%2A16 and this can be written as 16%5E2.
This gets multiplied by the remaining 16 to become:
.
%2816%5E2%29%2A16
.
If you now take the square root of this product you get:
.
sqrt%28%2816%5E2%29%2A16%29+=+sqrt%2816%5E2%29%2Asqrt%2816%29+=+16%2A4+=+64
.
Substituting this in to expression results in:
.
x-4+=+64
.
Finally, add 4 to both sides to get:
.
x+=+68
.
I hope you are able to follow all the detail. You can check the answer by substituting
this value for x into the original problem so that x-4 becomes 64. Then find the
cube root of 64 and square it. Or you may opt to square 64 and take the cube root of
that number. In both cases you should get 16, the same number as on the right side of
the original problem statement.