SOLUTION: what are the x & y intercepts of the circle with the equation (x-4)^2+(y+6)^2=13

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Question 697662: what are the x & y intercepts of the circle with the equation (x-4)^2+(y+6)^2=13
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
what are the x & y intercepts of the circle with the equation (x-4)^2+(y+6)^2=13
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The center is (4,-6)
The radius is less than 4
--> no intercepts