SOLUTION: The intensity of sound (in Watts per square meter, or "W"/"m" ^2) varies inversely with the distance from the source. Suppose that a particular sound has in intensity of 90 "W"/"m"

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Question 636618: The intensity of sound (in Watts per square meter, or "W"/"m" ^2) varies inversely with the distance from the source. Suppose that a particular sound has in intensity of 90 "W"/"m" ^2 at a distance of 5 meters. How much farther away would you find the intensity at 40 "W"/"m" ^2?

thanks so much for your help on this I really appreciate your time :)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The intensity of sound (in Watts per square meter, or "W"/"m" ^2) varies inversely with the distance from the source. Suppose that a particular sound has in intensity of 90 "W"/"m" ^2 at a distance of 5 meters. How much farther away would you find the intensity at 40 "W"/"m" ^2?
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W =k/d
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Solve for "k":
90 = k/5
k = 450
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Equation:
40 = 450/d
d = 450/40
d = 11 1/4 meters
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Cheers,
Stan H.
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