SOLUTION: write the equation of the circle in standard form. Find the center, radius, intercepts and graph the circle. x^2+y^2-10x-4y+13=0

Algebra ->  Rational-functions -> SOLUTION: write the equation of the circle in standard form. Find the center, radius, intercepts and graph the circle. x^2+y^2-10x-4y+13=0      Log On


   

Question 622801: write the equation of the circle in standard form. Find the center, radius, intercepts and graph the circle.
x^2+y^2-10x-4y+13=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, re Ty, Kudos to You, Spectacular!!! Keep Posting!!

x^2+y^2-10x-4y+13=0

x^2+y^2-10x-4y = -13

(x-5)^2 + (y-2)^2 = -13 + 25 + 4

%28x-5%29%5E2+%2B+%28y-2%29%5E2+=+16+=+r%5E2  C(5,2), r = 4 and 

 y = 0 ⇒ %28x-5%29%5E2+%2B+4+=+16   ⇒  x = 5 ± sqrt%2812%29