Question 548271: what is the equation of a line perpendicular to y=3x-7 and goes through (-3,-4)
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! 1 y = 3 x -7
Divide by 1
y = 3 x + -7
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 3
The slope of a line perpendicular to the above line will be the negative reciprocal
m1*m2=-1
The slope of the required line will be - 1/3
m= - 1/3 ,point ( -3 , -4 )
Find b by plugging the values of m & the point in
y=mx+b
-4=1.00+b
b=-5
m= - 1/3
The required equation is y=- (1/3)x-5
m.ananth@hotmail.ca
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