SOLUTION: graph y=(x+5)^2+5

Question 531502: graph y=(x+5)^2+5
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
y = (x+5)^2 + 5
y = x^2 +10x +25 +5
y = x^2 +10x +30
.
You know this is a parabola. So find several values of x to calculate values of y.
.
The axis of symmetry is where x = -b/2a.
-10/2 = -5
.
The vertex is where the parabola ends. It occurs on the axis of symmetry.
y = (-5)^2 +10(-5) + 30
y = 25 -50 + 30
y = 5
.
Pick several points to either side of the vertex.
x = -4, y = 6
x = -6, y = 6
x = 0, y = 30
x = -10, y = 30
x = 5, y = 105
x = -15, y = 105
.

RELATED QUESTIONS
graph... (answered by kmarcus1)

graph... (answered by checkley71)

GRAPH... (answered by checkley71)

Graph... (answered by Mathtut)

Graph y = | x | + 5... (answered by tommyt3rd)

Graph;... (answered by fractalier)

graph... (answered by MathLover1,josgarithmetic,math_tutor2020)

graph... (answered by rapaljer)

Graph the equation. y = x^2 -... (answered by jojo14344)