SOLUTION: How Do You Solve A Radical Equation. {{{ sqrt(x+1)= x-1 }}}

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Question 424586: How Do You Solve A Radical Equation. +sqrt%28x%2B1%29=+x-1+
Found 2 solutions by ankor@dixie-net.com, nerdybill:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
+sqrt%28x%2B1%29=+x-1+
Square both sides:
+%28sqrt%28x%2B1%29%29%5E2+=+%28x-1%29%5E2+
that gets rid of the radical, FOIL the right side (x-1)(x-1)
x + 1 = x^2 - 2x + 1
Combine like terms on the right
0 = x^2 - 2x - x + 1 - 1
0 = x^2 - 3x
Factor out x
x(x - 3) = 0
Two solutions
x = 0
and
x = 3
;
;
You can check both solutions in the original equation, note that x=0 is not a solution

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
+sqrt%28x%2B1%29=+x-1+
square both side:
+x%2B1+=+%28x-1%29%5E2+
+x%2B1+=+%28x-1%29%28x-1%29+
+x%2B1+=+x%5E2-2x%2B1+
+1+=+x%5E2-3x%2B1+
+0+=+x%5E2-3x+
+0+=+x%28x-3%29+
x = {0, 3}