SOLUTION: I am trying to simplify the sum of 5x/(x^2-x-6) and 4/(x^2+4*x+4). Please help.

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Question 33518This question is from textbook
: I am trying to simplify the sum of 5x/(x^2-x-6) and 4/(x^2+4*x+4). Please help. This question is from textbook

Found 2 solutions by Cintchr, longjonsilver:
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+%285x%2F%28x%5E2-x-6%29%29+%2B+%284%2F%28x%5E2%2B4%2Ax%2B4%29%29+
Factor the denominators
+%285x%2F%28%28x-3%29%28x%2B2%29%29%29+%2B+%284%2F%28%28x%2B2%29%28x%2B2%29%29%29+
Common denominator is : (x-3)(x+2)(x+2)

Distribute the 5x and 4 across in the numerators

Add the numerators
+%28%285x%5E2%2B10x%29%2B%284x%2B12%29%29%2F%28%28x-3%29%28x%2B2%29%28x%2B2%29%29+
+%28%285x%5E2%2B14x%2B12%29%29%2F%28%28x-3%29%28x%2B2%29%28x%2B2%29%29+
Since the numerator DOES NOT factor .... you are done

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
the answer given by the other tutor went wrong in the second fraction. They had (x+3) added. It should have been (x-3): or vice versa, i cannot remember... So that the denominators matched, so that the 2 fractions could be added.

Correct it yourself and work through the new algebra, to see what you get.

Jon.