SOLUTION: given k(x)={{{sqrt(x+1)}}} find k(-3) find k(-2) find k(-1) find k(0) find k(3) write the domain of k in interval notation construct the graph of k

Algebra ->  Rational-functions -> SOLUTION: given k(x)={{{sqrt(x+1)}}} find k(-3) find k(-2) find k(-1) find k(0) find k(3) write the domain of k in interval notation construct the graph of k      Log On


   



Question 328931: given k(x)=sqrt%28x%2B1%29
find k(-3)
find k(-2)
find k(-1)
find k(0)
find k(3)
write the domain of k in interval notation
construct the graph of k

Answer by solver91311(24713) About Me  (Show Source):
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Just plug in the value in the parentheses and do the arithmetic. Remember, the domain of square root is all reals greater than 0, hence any value of the independent variable that makes the radicand less than zero makes the function undefined.

Domain:




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John