SOLUTION: Can you help me solve for x? {{{sqrt(x^2+2)=x+4}}}

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Question 311736: Can you help me solve for x? sqrt%28x%5E2%2B2%29=x%2B4
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28x%5E2%2B2%29=x%2B4
Square both sides, (FOIL the right side
x^2 + 2 = x^2 + 8x + 16
:
combine the x's on the left
x^2 - x^2 - 8x = 16 - 2
:
-8x = 14
x = 14%2F%28-8%29
x = -1.75
:
:
Check solution in original equation
sqrt%28-1.75%5E2%2B2%29=-1.75%2B4
sqrt%283.0625%2B2%29=2.25
sqrt%285.0625%29=2.25
2.25 = 2.25