SOLUTION: 2m^3+3m^2-32m-48 polynomial factoring completely

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Question 302564: 2m^3+3m^2-32m-48
polynomial factoring completely
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

2m%5E3%2B3m%5E2-32m-48 Start with the given expression


%282m%5E3%2B3m%5E2%29%2B%28-32m-48%29 Group like terms


m%5E2%282m%2B3%29-16%282m%2B3%29 Factor out the GCF m%5E2 out of the first group. Factor out the GCF -16 out of the second group


%28m%5E2-16%29%282m%2B3%29 Since we have the common term 2m%2B3, we can combine like terms


%28m%2B4%29%28m-4%29%282m%2B3%29 Factor m%5E2-16 to get %28m%2B4%29%28m-4%29 (use difference of squares formula)


So 2m%5E3%2B3m%5E2-32m-48 factors to %28m%2B4%29%28m-4%29%282m%2B3%29


In other words, 2m%5E3%2B3m%5E2-32m-48=%28m%2B4%29%28m-4%29%282m%2B3%29