SOLUTION: Please help me!! And can you please show me how you did it?!?! Find the horizontal asymptote of f(x)=1/(x^2-16)

Algebra ->  Rational-functions -> SOLUTION: Please help me!! And can you please show me how you did it?!?! Find the horizontal asymptote of f(x)=1/(x^2-16)      Log On


   

Question 255949: Please help me!! And can you please show me how you did it?!?!
Find the horizontal asymptote of f(x)=1/(x^2-16)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me!! And can you please show me how you did it?!?!
Find the horizontal asymptote of f(x)=1/(x^2-16)
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1st: find the highest power of the variable.
It may be in the numerator or in the denominator.
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In your problem that is is x^2
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The numerator of your problem has zero x^2
The denominator of your problem has one x^2
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2nd: The horizontal asymptote is y = 0/1 or y = 0
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If you graph your problem you will see that the
horizontal asymptote is y = 0
graph%28400%2C300%2C-20%2C20%2C-2%2C2%2C1%2F%28x%5E2-16%29%29
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Cheers,
Stan H.