SOLUTION: I was told to solve by factoring. 4x^3-28x^2+49x>0 I thought that with factoring you have to have x2 x and a number. For some reason my mind is going blank. Please help if you

Algebra ->  Rational-functions -> SOLUTION: I was told to solve by factoring. 4x^3-28x^2+49x>0 I thought that with factoring you have to have x2 x and a number. For some reason my mind is going blank. Please help if you      Log On


   



Question 22914: I was told to solve by factoring.
4x^3-28x^2+49x>0
I thought that with factoring you have to have x2 x and a number. For some reason my mind is going blank. Please help if you can.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Factor:
4x%5E3+-28x%5E2+%2B+49x+%3E+0 First, factor out an x
x%284x%5E2+-+28x+%2B+49%29+%3E+0 Now factor the parentheses.
x%282x+-+7%29%282x+-+7%29+%3E+0 Does this help?