SOLUTION: add 3/(x+5) + 8(m^2-25) they are two fractions, 3 is the numerator of the first fraction and 8 is the numerator of the second fraction thank you veryy much

Algebra ->  Rational-functions -> SOLUTION: add 3/(x+5) + 8(m^2-25) they are two fractions, 3 is the numerator of the first fraction and 8 is the numerator of the second fraction thank you veryy much      Log On


   

Question 191965: add
3/(x+5) + 8(m^2-25)

they are two fractions, 3 is the numerator of the first fraction and 8 is the numerator of the second fraction

thank you veryy much
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
add
3/(x+5) + 8(m^2-25)
Assume you mean
add
3%2F%28m%2B5%29 + 8%2F%28m%5E2-25%29
m^2 - 25 is the difference of squares and can be factored
3%2F%28m%2B5%29 + 8%2F%28%28m-5%29%28m%2B5%29%29
therefore the common denominator is: (m-5)(m+5)
%283%28m-5%29+%2B+8%29%2F%28%28m-5%29%28m%2B5%29%29
:
%283m+-+15+%2B+8%29%2F%28%28m-5%29%28m%2B5%29%29
:
%283m+-+7%29%2F%28%28m-5%29%28m%2B5%29%29
or
%283m+-+7%29%2F%28m%5E2-25%29