Question 153251: 4x^2/3-27x^1/3-7=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 4x^2/3-27x^1/3-7=0
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Let x^(1/3) = w
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Substitute to get:
4w^2 - 27w - 7 = 0
Factor:
4w^2-28w+w-7 = 0
4w(w-7)+(w-7) = 0
(w-7)(4w+1) = 0
w = 7 or w = -1/4
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Substitute to get:
x^(1/3) = 7 or x^(1/3) = -1/4
x = 7^3 = 343 or x = -1/64
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Cheers,
Stan H.
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