SOLUTION: Find an equation of a line through (1,-3) that is perpendicular to 5x+2y=14

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Question 151053: Find an equation of a line through (1,-3) that is perpendicular to 5x+2y=14
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First find the slope of your original line.
5x%2B2y=14
2y=-5x%2B14
y=-%285%2F2%29%2B7
The slope of this line is,
m%5B1%5D=-%285%2F2%29
Perpendicular lines have slopes that are negative reciprocals of each other,
m%5B1%5Dm%5B2%5D=-1
-%285%2F2%29m%5B2%5D=-1
m%5B2%5D=2%2F5
Use the point-slope form of the line,
y-y%5B1%5D=m%28x-x%5B1%5D%29
y-%28-3%29=%282%2F5%29%28x-1%29
y%2B3=%282%2F5%29x-%282%2F5%29%29
y=%282%2F5%29x-%282%2F5%29-3%29
y=%282%2F5%29x-%282%2F5%29-%2815%2F5%29%29
y=%282%2F5%29x-%2817%2F5%29%29
Here are the two lines.