| 
 
 
| Question 127174:  I知 not sure if I have determined the correct value.  Could you please check my answer?
 (The symbol of a long slim S comes first) (4/x) dx over intervals (1, 3) = 4 Is that correct or did I miss something?  Thank you
 Also, would this formula (the symbol of a long slim S) e^x dx be completed at e^x or do I need to go farther?
 Thank you so much for your help again.  You folks are awesome!
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! The symbol of a long slim S comes first) (4/x) dx over intervals (1, 3) = 4 Is that correct or did I miss something? Thank you Also, would this formula (the symbol of a long slim S) e^x dx be completed at e^x or do I need to go farther?
 ----------------------
 That "long slim S" is an integral sign.
 ------
 int(4/x)dx evaluated from x=1 to x=3 is
 4lnx evaluated at x=3 - 4lnx evaluated at x=1
 You get: 4ln3-4ln1= 4(ln3-ln1) = 4(ln3-0) = 4ln3 = 4.3944...
 -------------
 int(e^x) = e^x + C, where C is any constant.
 You need the +C because your problem is an
 indefinate integral.
 ===============
 Cheers,
 stan H.
 
 | 
  
 | 
 |