SOLUTION: A small manufacturing makes and sells x machines each month. The monthly cost, C ,in dollars, of making x dollars is given by C(x)= 0.35x^2 + 3200 The monthly revenue, R, in doll

Algebra ->  Rational-functions -> SOLUTION: A small manufacturing makes and sells x machines each month. The monthly cost, C ,in dollars, of making x dollars is given by C(x)= 0.35x^2 + 3200 The monthly revenue, R, in doll      Log On


   



Question 1173375: A small manufacturing makes and sells x machines each month. The monthly cost, C ,in dollars, of making x dollars is given by
C(x)= 0.35x^2 + 3200
The monthly revenue, R, in dollars, obtained by selling x machines is given by
R(x)= 180x - 0.55x^2
If the company does maximum profit what is the selling price of each machine?

Found 2 solutions by CubeyThePenguin, ikleyn:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
Profit is revenue minus cost.

R%28x%29+-+C%28x%29+=+%28180x+-+0.55x%5E2%29+-+%280.35x%5E2+%2B+3200%29

-0.9x%5E2+%2B+180x+-+3200

The maximum is at -b/2a = 100.

The selling price of every machine is R(x) divided by x, or 125 dollars.

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

Your formulation is FATALLY WRONG,

and I came to fix it.

See my editing below.


    A small manufacturing makes and sells x machines each month. The monthly cost, C ,in dollars, 
    of making x highlight%28cross%28dollars%29%29 MACHINES is given by

        C(x)= 0.35x^2 + 3200

    The monthly revenue, R, in dollars, obtained by selling x machines is given by

        R(x)= 180x - 0.55x^2

    If the company does maximum profit what is the selling price of each machine?