SOLUTION: A triangular garden has two equal sides 3.6 m long and a contained angle of 80°. Draw and
label a diagram.
a) How much fencing, to the nearest metre, is needed for this garden?
Algebra ->
Rational-functions
-> SOLUTION: A triangular garden has two equal sides 3.6 m long and a contained angle of 80°. Draw and
label a diagram.
a) How much fencing, to the nearest metre, is needed for this garden?
Log On
Question 1173353: A triangular garden has two equal sides 3.6 m long and a contained angle of 80°. Draw and
label a diagram.
a) How much fencing, to the nearest metre, is needed for this garden?
b) How much area does the garden cover? Round your answer to the nearest tenth of a square metre Answer by ewatrrr(24785) (Show Source):
Hi
After sketching a line down representing the height of the isosceles Triangle,
dividing the triangle equally, following applies per sketch of left half
hypotenuse = 3.6m
Angle A = 90° - 80°/2 =50°
cos50° = adj/hyp =b/2.6 ( b= B/2) and sin50° =opp/hyp= height/2.6
b = 2.6cos50° = 1.7m = 3.4m and height = 2.6sin50° = 1.99 m
a) amount of fencing = 2.6m +2.6m + 3.4m
b) Area = (3.4m)(1.99m)/2
