SOLUTION: An object is launched from ground level directly upward at a rate of 144 feet per second. The equation for the object’s height is 0 = -16x2 + 144x. What values of x is the obje

Algebra ->  Rational-functions -> SOLUTION: An object is launched from ground level directly upward at a rate of 144 feet per second. The equation for the object’s height is 0 = -16x2 + 144x. What values of x is the obje      Log On


   

Question 1169809: An object is launched from ground level directly upward at a rate of 144 feet per
second. The equation for the object’s height is 0 = -16x2 + 144x. What values of
x is the object at OR ABOVE a height of 288 feet? How long is the object at or
above this height?
Answer by ikleyn(52909) About Me  (Show Source):
You can put this solution on YOUR website!
.

The equation for the height is written incorrectly in your post.

See the lessons
    - Introductory lesson on a projectile thrown-shot-launched vertically up
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform

Consider these lessons as your textbook,  handbook,  tutorials and  (free of charge)  home teacher.
Read them attentively and learn how to solve this type of problems once and for all.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.