SOLUTION: The equation of the line which is perpendicular to 3y=2x-6, and passes through the point (4,7)

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Question 1137286: The equation of the line which is perpendicular to 3y=2x-6, and passes through the point (4,7)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The equation of the line which is perpendicular to 3y=2x-6, and passes through the point (4,7)
3y = 2x - 6

2x - 3y = 6 ------ Converting to STANDARD FORM of a linear function

If in the above form, Ax - By = C, KEEP A the same, NEGATE B and then switch coefficients to get left side of equation. This gives us: 3x + 2y = C

Now, C is calculated based on the given point and the left side of the equation.

This results in: 

That's IT!!