SOLUTION: Find the x-intercept(s) and the coordinates of the vertex for the parabola y=x^2+6x-7

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Question 1063261: Find the x-intercept(s) and the coordinates of the vertex for the parabola
y=x^2+6x-7
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B6x-7=0
%28x%2B7%29%28x-1%29=0
x-intercepts are -7, and +1.

The value in the exact middle of these intercepts and on the x-axis is %28-7%2B1%29%2F2=-3.

Vertex will be at system%28x=-3%2Cy=%28-3%29%5E2%2B6%28-3%29-7=9-18-7=-16%29, or the point (-3,-16).