SOLUTION: solve for x x^4+2x/x^2-1=0 in a solution they got =>(x^4+2x)(x^2-1)/(x^2-1)^2 =0 and then =>x=-2^(1/3),-1,0,1 how did they get this? Thanks in advance!

Algebra ->  Rational-functions -> SOLUTION: solve for x x^4+2x/x^2-1=0 in a solution they got =>(x^4+2x)(x^2-1)/(x^2-1)^2 =0 and then =>x=-2^(1/3),-1,0,1 how did they get this? Thanks in advance!      Log On


   

Question 1025161: solve for x
x^4+2x/x^2-1=0 in a solution they got
=>(x^4+2x)(x^2-1)/(x^2-1)^2 =0
and then =>x=-2^(1/3),-1,0,1
how did they get this? Thanks in advance!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I think this is your equation although you didn't use any parentheses.
%28x%5E4%2B2x%29%2F%28x%5E2-1%29=0
So you need to solve when the numerator is equal to zero,
x%28x%5E3%2B2%29=0
Two solutions:
x=0
and
x%5E3=-2
x=%28-2%29%5E%281%2F3%29
Not sure about the other two solutions.
I also looked at
%28x%5E4%2B2x%29%2F%28x%5E2%29-1=0
But that didn't yield your solutions either.
If you need repost and add parentheses to your equation.