SOLUTION: It takes John 4 times as long as it takes Jessica to mow a lawn. If it took them both 11 hours to mow the lawn, how long would it take John to mow the lawn alone?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: It takes John 4 times as long as it takes Jessica to mow a lawn. If it took them both 11 hours to mow the lawn, how long would it take John to mow the lawn alone?      Log On


   

Question 964722: It takes John 4 times as long as it takes Jessica to mow a lawn. If it took them both 11 hours to mow the lawn, how long would it take John to mow the lawn alone?
Found 3 solutions by josgarithmetic, addingup, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Jessica, 1%2Fx
John, 1%2F%284x%29

You could also say,
Jessica, 4%2Ft
John, 1%2Ft


The choice of x or t was arbitrary.

%284%2Ft%2B1%2Ft%29%2A11=1------this form will make answering the question asked be a little easier. Solve for t.

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!

4times Jessica + Jessica= 11 In one hour:
1/4j+1/j= 1/11 Multiply all denominators by 11j
11/4+11= j
11/4+44/4= j
55/4=j
j= 13.75 hours it takes John. And Jessica? Well, 13.75/3= 3.44 hours.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

It takes John 4 times as long as it takes Jessica to mow a lawn. If it took them both 11 hours to mow the lawn, how long would it take John to mow the lawn alone?
Time it takes John, alone: highlight_green%2855%29 hours