SOLUTION: six tapes fill a empty cistern in 8 hours. How much more time will be taken if two tapes go out of orders. Assume all the tapes supply water at the same rate.

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Question 950682: six tapes fill a empty cistern in 8 hours. How much more time will be taken if two tapes go out of orders. Assume all the tapes supply water at the same rate.
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assume you mean:
Six taps fill a empty cistern in 8 hours.
6 * 8 = 48 tap-hrs required
How much more time will be taken if two taps go out of order.
let t = time required by the 4 remaining taps
4t = 48
t = 12 hrs required by 4 taps
But it asks how much more time.
12 - 8 = 4 more hrs

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
One working alone takes +6%2A8+=+48+ hrs
to fill a cistern
Four of them take +%28+1%2F4+%29%2A%28+48+%29+=+12+ hrs
Six of them take +8+ hrs
The difference in time is +12+-+8+=+4+ hrs more