SOLUTION: One pump can fill a pool in 10 hr. Working with a second slower pump, the two pumps together can fill the pool in 6 hr. How fast can the second pump fill the pool by itself?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: One pump can fill a pool in 10 hr. Working with a second slower pump, the two pumps together can fill the pool in 6 hr. How fast can the second pump fill the pool by itself?      Log On


   

Question 900179: One pump can fill a pool in 10 hr. Working with a second slower pump, the two pumps together can fill the pool in 6 hr. How fast can the second pump fill the pool by itself?
Found 2 solutions by nathany1280, josgarithmetic:
Answer by nathany1280(5) About Me  (Show Source):
You can put this solution on YOUR website!
the first pump obviously pumps faster and pumps in 10hr. with the 2nd pump, it pumps in 6hr. You would do 10-6 because you know how long the first one pumps and you subtract it to find how much faster does the 2nd one pump. then you add 4 to the 10 which is 14hr.

Answer: 14hr for the 2nd pump to fill the pool

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
You can think of this tank or pool filling as a doing a job or a work problem with uniform rates.

RT=J and 1 job is "fill the pool".

Rates:
Regular pump, 1%2F10
Slower pump, 1%2Fx
Combined pumps, 1%2F6

You only have the addition of rates, because they are like "moving in the same direction" when they work together.

highlight_green%281%2F10%2B1%2Fx=1%2F6%29
LCD is 30x.
Multiply both sides by 30x.
3x%2B30=5x
30=2x
highlight%28x=15%29------The time in HOURS for the slower pump to fill the pool if working alone.