SOLUTION: Rafael designed a sequined dress to be worn at the a academy awards. maris can sew all the dequins in 10 hr less time than stephanie. to save time he gave the job to both women a
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-> SOLUTION: Rafael designed a sequined dress to be worn at the a academy awards. maris can sew all the dequins in 10 hr less time than stephanie. to save time he gave the job to both women a
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Question 824800: Rafael designed a sequined dress to be worn at the a academy awards. maris can sew all the dequins in 10 hr less time than stephanie. to save time he gave the job to both women and got all the sequins attached in 17 hrs. how long would it have taken stephanie working alone. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Rafael designed a sequined dress to be worn at the a academy awards. maris can sew all the dequins in 10 hr less time than stephanie. to save time he gave the job to both women and got all the sequins attached in 17 hrs. how long would it have taken stephanie working alone.
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Stephanie:: time = x hr/job ; rate = 1/x job/hr
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Maris:::::: time = x-10 hr/job ; rate = 1/(x-10) job/hr
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Together time:: time = 17 hr/job ; rate = 1/17 job/hr
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Equation:
rate + rate = together rate
1/x + 1/(x-10) = 1/17
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17(x-10) + 17x = x(x-10)
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34x - 170 = x^2 - 10x
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x^2 -44x + 170 = 0
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x = 4.28 (extraneous for then x-10 would be negative)
x = 39.72 hrs (stephaney's time alone)
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Cheers,
Stan H.
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