15 workers finish a work in 8 days. How many days would be taken from 12 workers to finish the same work?
-----------------------------------------------------------------------
Method 1:
The least common multiple of 15 workers and 12 workers is 60 workers.
15 workers is 1/4th of 60 workers and 12 workers is 1/5th of 60 workers.
15 workers finish a work in 8 days. 
So 4 times as many workers can finish the work in 1/4 the time.
So 60 workers can finish it in only 2 days.
So one-fifth as many workers will take 5 times as long, or 10 days.
-----------------
Method 2:
You can also use the worker-time-job formula, which is:


 where
W1 = the number of workers in the first situation.
T1 = the number of time units (days in this case) in the first situation.
J1 = the number of jobs in the first situation.
W2 = the number of workers in the second situation.
T2 = the number of time units (days in this case) in the second situation.
J2 = the number of jobs in the second situation.
W1 = 15             W2 = 12     
T1 =  8             T2 = the unknown quanity
J1 =  1             J2 = 1
where
W1 = the number of workers in the first situation.
T1 = the number of time units (days in this case) in the first situation.
J1 = the number of jobs in the first situation.
W2 = the number of workers in the second situation.
T2 = the number of time units (days in this case) in the second situation.
J2 = the number of jobs in the second situation.
W1 = 15             W2 = 12     
T1 =  8             T2 = the unknown quanity
J1 =  1             J2 = 1


 


 15*8 = 12*T2
 120 = 12*T2
15*8 = 12*T2
 120 = 12*T2
  = T2
  10 = T2 
Answer 10 days.
Edwin
 = T2
  10 = T2 
Answer 10 days.
Edwin