SOLUTION: It takes Jeff 90 mins. to mow the yard. It takes Joe 105 mins to mow the yard. What is the approximate time it will take if they work together to mow the yard? this is the p

Algebra ->  Rate-of-work-word-problems -> SOLUTION: It takes Jeff 90 mins. to mow the yard. It takes Joe 105 mins to mow the yard. What is the approximate time it will take if they work together to mow the yard? this is the p      Log On


   



Question 723565: It takes Jeff 90 mins. to mow the yard. It takes Joe 105 mins to mow the yard. What is the approximate time it will take if they work together to mow the yard? this is the problem, how do I work it out? thanks
Found 3 solutions by checkley79, AnlytcPhil, Edwin McCravy:
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
1/90+1/105=1/X FIND A COMMON DENOMINATOR FOR THE LEFT HAND FRACTIONS.
(105+90)/90*105=1/X
195/9,450-1/X CROSS MULTIPLY.
195X=9,450
X=9.450/195
X=48.46 MINS. ANS.

Answer by AnlytcPhil(1806) About Me  (Show Source):
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Here it is broken down so you can understand where everything comes from.

It takes Jeff 90 mins. to mow the yard.
Therefore Jeff's mowing rate is 1 lawn per 90 minutes or 1_lawn%2F90_min or 1%2F90lawn%2Fmin

It takes Joe 105 mins to mow the yard.
Therefore Joe's mowing rate is 1 lawn per 105 minutes or 1_lawn%2F105_min or 1%2F105lawn%2Fmin

What is the approximate time it will take if they work together to mow the yard?
Let x be the answer, Then it takes them x mins to mow the yard working
together.
Therefore their combined mowing rate is 1 lawn per x minutes or 1_lawn%2Fx_min or 1%2Fxlawn%2Fmin 

The equation comes from:

                  %22%22%2B%22%22%22%22=%22%22

                      1%2F90lawn%2Fmin%22%22%2B%22%221%2F105lawn%2Fmin%22%22=%22%221%2Fxlawn%2Fmin

                             1%2F90%22%22%2B%22%221%2F105%22%22=%22%221%2Fx

Solve that by multiplying through by 630x

Answer 48%266%2F13 minutes.


Edwin